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Answer:

(i) CH3–CH=CH2 + HBr → CH3–CHBr–CH3 (2-bromopropane). By Markovnikov’s rule the H adds to the carbon with more hydrogen atoms and Br to the other carbon (via the more stable secondary carbocation).

(ii) C2H5OH + SOCl2 —(Δ, pyridine)→ C2H5Cl + SO2↑ + HCl↑ (chloroethane). The by-products are gases and escape, so pure alkyl chloride is obtained.

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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