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Answer: pH = 10.30

Conjugate acid-base pair: An acid and a base that differ from each other only by one proton (H+) form a conjugate acid-base pair. E.g. in HCl + H2O ⇌ H3O+ + Cl−, HCl/Cl− and H3O+/H2O are conjugate pairs.

Calculation: \([\mathrm{OH^-}] = 2\times10^{-4}\) M

\(\mathrm{pOH} = -\log(2\times10^{-4}) = 4 - \log 2 = 4 - 0.3010 = 3.699\)

\(\mathrm{pH} = 14 - \mathrm{pOH} = 14 - 3.699 = 10.301\)

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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