Derive Ostwald’s dilution law equation for a weak acid.
Q.4 Derive Ostwald’s dilution law equation for a weak acid.
Q.4 Derive Ostwald’s dilution law equation for a weak acid.
Best answer
Answer: \(K_a = \dfrac{\alpha^2 c}{1-\alpha} \approx \alpha^2 c\), so \(\alpha = \sqrt{K_a/c}\).
Consider a weak acid HA of concentration \(c\) mol dm–3 with degree of dissociation \(\alpha\):
| HA | ⇌ H+ | + A– | |
|---|---|---|---|
| Initial | \(c\) | 0 | 0 |
| At equilibrium | \(c(1-\alpha)\) | \(c\alpha\) | \(c\alpha\) |
\(K_a = \dfrac{[\text{H}^+][\text{A}^-]}{[\text{HA}]} = \dfrac{c\alpha \cdot c\alpha}{c(1-\alpha)} = \dfrac{\alpha^2 c}{1-\alpha}\)
For a weak acid \(\alpha\) is very small, so \(1-\alpha \approx 1\): \(K_a = \alpha^2 c\) and \(\alpha = \sqrt{\dfrac{K_a}{c}}\). Thus the degree of dissociation increases with dilution (Ostwald’s dilution law).
Log in or create a free account to answer this question.