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Answer: (a) 4.90 BM; (b) [Xe] 4f7 5d1 6s2

(a) M (Z = 26) is Fe: [Ar]3d64s2. M2+: [Ar]3d6, which has 4 unpaired electrons (n = 4).

\(\mu = \sqrt{n(n+2)} = \sqrt{4 \times 6} = \sqrt{24} = 4.90\) BM

(b) Gd (Z = 64): [Xe] 4f7 5d1 6s2 (the half-filled 4f7 is extra stable, so one electron goes into 5d).

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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