\(\int_{-9}^{9}\frac{x^3}{4-x^2}\,dx\) = _____.
Q.1 (A) (vi) \(\int_{-9}^{9}\frac{x^3}{4-x^2}\,dx\) = _____.
A. 1
B. 0
C. \(-1\)
D. \(\frac{3x^2}{(4-x^2)^2}\)
Q.1 (A) (vi) \(\int_{-9}^{9}\frac{x^3}{4-x^2}\,dx\) = _____.
A. 1
B. 0
C. \(-1\)
D. \(\frac{3x^2}{(4-x^2)^2}\)
Best answer
Answer: B. 0
Answer: (b) 0
Let \(f(x)=\frac{x^3}{4-x^2}\). Then \(f(-x)=\frac{-x^3}{4-x^2}=-f(x)\), so \(f\) is an odd function. For an odd function \(\int_{-a}^{a}f(x)\,dx=0\).
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