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Following table shows the number of traffic fatalities (in a state) resulting from drunken driving from years 1975 to 1983:Years197519761977197819791980198119821983No. of deaths0638294510Fit a trend line by least square method.

Q.6 (A) (iii) Following table shows the number of traffic fatalities (in a state) resulting from drunken driving from years 1975 to 1983:

Years197519761977197819791980198119821983
No. of deaths0638294510

Fit a trend line by least square method.

1 answer

Best answer

Answer: \(y=5.222+0.667u\), where \(u=t-1979\)

\(n=9\) (odd), so take \(u=t-1979\).

Year \(t\)\(y\)\(u=t-1979\)\(u^2\)\(uy\)
19750−4160
19766−39−18
19773−24−6
19788−11−8
19792000
19809119
19814248
198253915
19831041640
Total4706040

Trend line \(y=a+bu\) with \(a=\frac{\sum y}{n}=\frac{47}{9}=5.222\) and \(b=\frac{\sum uy}{\sum u^2}=\frac{40}{60}=0.667\).

\(\therefore\) The trend line is \(y=5.222+0.667u\), \(u=t-1979\). (Trend values: 1975: 2.555, 1979: 5.222, 1983: 7.889.)

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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