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The equations of two regression lines are \(16y+x=64\) and \(x+4y=5\). Find regression coefficients and correlation coefficient.Solution:Suppose that equation of regression line of \(Y\) on \(X\) be \(16y+x=64\) and equation of regression line of \(X…

Q.6 (C) (ii) The equations of two regression lines are \(16y+x=64\) and \(x+4y=5\). Find regression coefficients and correlation coefficient.

Solution:
Suppose that equation of regression line of \(Y\) on \(X\) be \(16y+x=64\) and equation of regression line of \(X\) on \(Y\) be \(x+4y=5\)
Now \(16y+x=64\) and \(x+4y=5\)
\(\therefore y=\frac{-1}{16}x+4\) and \(x=-4y+5\)
\(\therefore b_{yx}=\)[ ] and \(b_{xy}=\)[ ]
\(b_{yx}\times b_{xy}=\frac{1}{4}\)
\(\therefore b_{yx}\times b_{xy}\lt 1\)
\(\therefore\) Our assumption is correct.
\(\therefore r^2=\)[ ]
\(\therefore r=\)[ ]

1 answer

Best answer

Answer: Boxes: \(b_{yx}=-\frac{1}{16}\); \(b_{xy}=-4\); \(r^2=\frac{1}{4}\); \(r=-\frac{1}{2}\)

From \(y=-\frac{1}{16}x+4\): \(b_{yx}=\boxed{-\frac{1}{16}}\). From \(x=-4y+5\): \(b_{xy}=\boxed{-4}\).

\(b_{yx}\times b_{xy}=\left(-\frac{1}{16}\right)(-4)=\frac{1}{4}\lt 1\), so the assumption is correct.

\(r^2=b_{yx}\cdot b_{xy}=\boxed{\frac{1}{4}}\). Since both regression coefficients are negative, \(r\) is negative: \(r=\boxed{-\frac{1}{2}}=-0.5\).

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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