Skip to content
doubtly

1 answer

Best answer

Answer: \(\operatorname{adj} A = \begin{bmatrix} 3 & 2 \\ -4 & 2 \end{bmatrix}\)

Let \(A = \begin{bmatrix} 2 & -2 \\ 4 & 3 \end{bmatrix}\). Cofactors: \(A_{11} = 3\), \(A_{12} = -4\), \(A_{21} = -(-2) = 2\), \(A_{22} = 2\).

Cofactor matrix \(= \begin{bmatrix} 3 & -4 \\ 2 & 2 \end{bmatrix}\); its transpose gives \(\operatorname{adj} A = \begin{bmatrix} 3 & 2 \\ -4 & 2 \end{bmatrix}\).

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.