Skip to content
doubtly

1 answer

Best answer

Answer: \(\begin{bmatrix} 6 & 1 \\ -2 & 5 \end{bmatrix}\)

Let \(A = \begin{bmatrix} 5 & 2 \\ -1 & 6 \end{bmatrix}\). Cofactor \(A_{ij} = (-1)^{i+j}M_{ij}\).

  • \(A_{11} = (-1)^2(6) = 6\)
  • \(A_{12} = (-1)^3(-1) = 1\)
  • \(A_{21} = (-1)^3(2) = -2\)
  • \(A_{22} = (-1)^4(5) = 5\)

Matrix of cofactors \(= \begin{bmatrix} 6 & 1 \\ -2 & 5 \end{bmatrix}\).

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.