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Answer: (i) \(\dfrac{1}{1024}\) (ii) \(\dfrac{243}{1024}\)

Since the draws are with replacement, they are independent trials. Let \(X\) = number of spades; \(p = \dfrac{13}{52} = \dfrac14\), \(q = \dfrac34\), \(n = 5\). So \(X \sim B\left(5, \frac14\right)\) and \(P(X = x) = {}^5C_x\left(\frac14\right)^x\left(\frac34\right)^{5-x}\).

(i) \(P(X = 5) = \left(\dfrac14\right)^5 = \dfrac{1}{1024}\).

(ii) \(P(X = 0) = \left(\dfrac34\right)^5 = \dfrac{243}{1024}\).

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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