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Answer: D. 0

Answer: (d) 0

At \(x = 0\): \(\log y = 0\), so \(y = 1\). Differentiating \(\log(x + y) = xy\) w.r.t. \(x\): \(\frac{1}{x + y}\left(1 + \frac{dy}{dx}\right) = y + x\frac{dy}{dx}\). Put \(x = 0,\ y = 1\): \(1 + \frac{dy}{dx} = 1\), so \(\frac{dy}{dx} = 0\).

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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