Q.2 (iii) Find dy/dx , if y = sin(log x) .

Answer: dy/dx = cos(log x)/x By the chain rule, dy/dx = cos(log x)·d/dx(log x) = cos(log x)/x .

Find \(\frac{dy}{dx}\), if \(y = \sin(\log x)\).

Q.2 (iii) Find \(\frac{dy}{dx}\), if \(y = \sin(\log x)\).

Doubtly Asked 28 Oct 2026 Board exam · July 2025 hsc 12th Save WhatsApp Report

Best answer

Answer: \(\frac{dy}{dx} = \frac{\cos(\log x)}{x}\)

By the chain rule, \(\frac{dy}{dx} = \cos(\log x)\cdot\frac{d}{dx}(\log x) = \frac{\cos(\log x)}{x}\).

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report

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