When 6.0 g of O2 reacts with ClF as per2ClF(g) + O2(g) → Cl2O(g) + OF2(g)The enthalpy change is 38.55 kJ. Calculate the standard enthalpy of the reaction.

Q.2 (viii) When 6.0 g of O₂ reacts with ClF as per
2ClF_(g) + O_2(g) → Cl₂O_(g) + OF_2(g)
The enthalpy change is 38.55 kJ. Calculate the standard enthalpy of the reaction.

Doubtly Asked 28 Oct 2026 Board exam · July 2025 hsc 12th Save WhatsApp Report

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Answer: \(\Delta_r H^\circ = +205.6\) kJ

Moles of O₂ \(= \dfrac{6.0}{32} = 0.1875\) mol. The equation is written for 1 mol O₂, so \(\Delta_r H^\circ = \dfrac{38.55\ \text{kJ}}{0.1875\ \text{mol}} \times 1\ \text{mol} = 205.6\) kJ.

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report

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When 6.0 g of O2 reacts with ClF as per2ClF(g) + O2(g) → Cl2O(g) + OF2(g)The enthalpy change is 38.55 kJ. Calculate the standard enthalpy of the reaction.

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