Skip to content
doubtly

1 answer

Best answer

Answer: \(W_{max} = -1717\) J \(\approx -1.72\) kJ

Given: mass of O2 = 32 g, M = 32 g mol–1, so \(n = 1\) mol; \(P_1 = 2\) bar, \(P_2 = 1\) bar, \(T = 298\) K, \(R = 8.314\) J K–1 mol–1.

\(W_{max} = -2.303\,nRT\log_{10}\dfrac{P_1}{P_2}\)

\(= -2.303 \times 1 \times 8.314 \times 298 \times \log_{10} 2\)

\(= -2.303 \times 8.314 \times 298 \times 0.3010 = -1717\) J

The negative sign shows that work is done by the gas on the surroundings.

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.