Q.10 An aircraft of wing span of 60 m flies horizontally in earth's magnetic field of 6×10⁻⁵ T at a speed of 500 m/s. Calculate the e.m.f. induced between the tips of wings of aircraft.

Answer: e = 1.8 V Given: l = 60 m, B = 6×10⁻⁵ T, v = 500 m/s. Motional e.m.f.: e = Blv = 6×10⁻⁵× 60× 500 = 1.8 V. (Here B is taken as the component of the earth's field perpendicular to the plane in which the wings move.)

Chapter: Electromagnetic induction· Physics

An aircraft of wing span of 60 m flies horizontally in earth's magnetic field of \(6\times10^{-5}\) T at a speed of 500 m/s. Calculate the e.m.f. induced between the tips of wings of aircraft.

Q.10 An aircraft of wing span of 60 m flies horizontally in earth's magnetic field of \(6\times10^{-5}\) T at a speed of 500 m/s. Calculate the e.m.f. induced between the tips of wings of aircraft.

Doubtly Asked 29 Oct 2026 Board exam · March 2024 hsc 12th Save WhatsApp Report

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Answer: e = 1.8 V

Given: \(l = 60\) m, \(B = 6\times10^{-5}\) T, \(v = 500\) m/s.

Motional e.m.f.: \(e = Blv = 6\times10^{-5}\times 60\times 500 = 1.8\) V.

(Here B is taken as the component of the earth's field perpendicular to the plane in which the wings move.)

Doubtly AI · 29 Oct 2026 AI-generated · not yet verified Report

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An aircraft of wing span of 60 m flies horizontally in earth's magnetic field of \(6\times10^{-5}\) T at a speed of 500 m/s. Calculate the e.m.f. induced between the tips of wings of aircraft.

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