Chapter: Electromagnetic induction· Physics

A search coil having 2000 turns with area 1.5 cm2 is placed in a magnetic field of 0.6T. The coil is moved rapidly out of the field in a time of 0.2 second. Calculate the induced emf across the search coil.

Q.23 A search coil having 2000 turns with area 1.5 cm² is placed in a magnetic field of 0.6T. The coil is moved rapidly out of the field in a time of 0.2 second. Calculate the induced emf across the search coil.

Doubtly Asked 29 Oct 2026 Board exam · July 2024 hsc 12th Save WhatsApp Report

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Answer: \(e = 0.9\) V

Given \(N = 2000\), \(A = 1.5\) cm\(^2\) \(= 1.5\times10^{-4}\) m\(^2\), \(B = 0.6\) T, \(dt = 0.2\) s. The coil is taken out of the field, so the flux through each turn changes from \(BA\) to zero.

Change of flux per turn: \(d\phi = BA = 0.6\times1.5\times10^{-4} = 9\times10^{-5}\) Wb.

By Faraday’s law, the magnitude of the induced emf is

\[e = \frac{N\,d\phi}{dt} = \frac{2000\times9\times10^{-5}}{0.2} = \frac{0.18}{0.2} = 0.9\ \mathrm{V}\]

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A search coil having 2000 turns with area 1.5 cm2 is placed in a magnetic field of 0.6T. The coil is moved rapidly out of the field in a time of 0.2 second. Calculate the induced emf across the search coil.

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