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Answer: \(\Delta L = -\dfrac{h}{\pi} \approx -2.11\times10^{-34}\) J s (a decrease of \(2.11\times10^{-34}\) J s)

By Bohr's postulate, \(L_n = \dfrac{nh}{2\pi}\).

\(\Delta L = L_1 - L_3 = \dfrac{h}{2\pi}(1 - 3) = -\dfrac{2h}{2\pi} = -\dfrac{h}{\pi}\)

\(= -\dfrac{6.63\times10^{-34}}{3.142} = -2.11\times10^{-34}\) J s.

The angular momentum decreases by \(2.11\times10^{-34}\) J s.

Doubtly AI · 29 Oct 2026 AI-generated · not yet verified Report
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