Chapter: Structure of Atoms and Nuclei· Physics

An electron in hydrogen atom stays in its second orbit for 10–8 s. How many revolutions will it make around the nucleus in that time?[ Velocity of electron in second orbit = 1.07 × 106 m/s, radius of electron in second orbit = 2.14 × 10–10 m]

Q.11 An electron in hydrogen atom stays in its second orbit for 10^–8 s. How many revolutions will it make around the nucleus in that time?
[ Velocity of electron in second orbit = 1.07 × 10⁶ m/s, radius of electron in second orbit = 2.14 × 10^–10 m]

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Answer: About \(7.96\times10^{6}\) revolutions.

Time for one revolution:

\[T = \frac{2\pi r}{v} = \frac{2\times3.142\times2.14\times10^{-10}}{1.07\times10^{6}} = 2\times3.142\times2\times10^{-16} = 1.257\times10^{-15}\ \mathrm{s}\]

Number of revolutions in \(10^{-8}\) s:

\[N = \frac{10^{-8}}{1.257\times10^{-15}} = 7.96\times10^{6}\]

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An electron in hydrogen atom stays in its second orbit for 10–8 s. How many revolutions will it make around the nucleus in that time?[ Velocity of electron in second orbit = 1.07 × 106 m/s, radius of electron in second orbit = 2.14 × 10–10 m]

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