Distinguish between an ammeter and a voltmeter. (Two points each).The displacement of a particle performing simple harmonic motion is \(\dfrac{1}{3}\)rd of its amplitude. What fraction of total energy will be its kinetic energy?

Q.29 Distinguish between an ammeter and a voltmeter. (Two points each).

The displacement of a particle performing simple harmonic motion is \(\dfrac{1}{3}\)rd of its amplitude. What fraction of total energy will be its kinetic energy?

Doubtly Asked 29 Oct 2026 Board exam · March 2024 hsc 12th Save WhatsApp Report

1 answer

Best answer

Answer: (Differences in the table below.) Kinetic energy \(= \dfrac{8}{9}\) of the total energy.

Ammeter	Voltmeter
1. It measures the electric current in a circuit.	1. It measures the potential difference between two points of a circuit.
2. It is always connected in series in the circuit.	2. It is always connected in parallel (across) the part of the circuit.
3. Its resistance is very low; ideal ammeter has zero resistance.	3. Its resistance is very high; ideal voltmeter has infinite resistance.
4. It is made by connecting a low resistance (shunt) in parallel with a galvanometer.	4. It is made by connecting a high resistance in series with a galvanometer.

SHM problem: Given \(x = \dfrac{A}{3}\).

Total energy \(E = \dfrac{1}{2}m\omega^2A^2\); kinetic energy \(K = \dfrac{1}{2}m\omega^2(A^2 - x^2)\).

\(\dfrac{K}{E} = \dfrac{A^2 - x^2}{A^2} = 1 - \dfrac{x^2}{A^2} = 1 - \dfrac{1}{9} = \dfrac{8}{9}\).

So the kinetic energy is \(\dfrac{8}{9}\) of the total energy (and the potential energy is \(\dfrac{1}{9}\)).

Doubtly AI · 29 Oct 2026 AI-generated · not yet verified Report

Was this answer helpful?

Distinguish between an ammeter and a voltmeter. (Two points each).The displacement of a particle performing simple harmonic motion is \(\dfrac{1}{3}\)rd of its amplitude. What fraction of total energy will be its kinetic energy?

1 answer

Your answer