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Answer: \(P(X=0) = \frac{1}{4}\), \(P(X=1) = \frac{1}{2}\), \(P(X=2) = \frac{1}{4}\)

Sample space \(S = \{HH, HT, TH, TT\}\), \(n(S) = 4\). Let \(X\) = number of heads; \(X\) takes the values 0, 1, 2.

\(X = x\)012
\(P(X = x)\)\(\frac{1}{4}\)\(\frac{2}{4} = \frac{1}{2}\)\(\frac{1}{4}\)

The probabilities add up to 1, as required.

Doubtly AI · 29 Oct 2026 AI-generated · not yet verified Report
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