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Chapter: Trigonometry· Mathematics Part 2 (Geometry)

Asked in: July 2024 and March 2026 board papersIf \(\sec\theta = \dfrac{25}{7}\), complete the following activity to find the value of \(\tan\theta\).Activity: We have, \(1 + \tan^2\theta = \sec^2\theta\)\(\therefore 1 + \tan^2\theta = \text{____}\)\…

Asked in: July 2024 and March 2026 board papers

If \(\sec\theta = \dfrac{25}{7}\), complete the following activity to find the value of \(\tan\theta\).

Activity: We have, \(1 + \tan^2\theta = \sec^2\theta\)

\(\therefore 1 + \tan^2\theta = \text{____}\)

\(\therefore \tan^2\theta = \dfrac{625}{49} - \text{____}\)

\(\therefore \tan^2\theta = \dfrac{625 - 49}{49}\)

\(\therefore \tan^2\theta = \dfrac{\text{____}}{49}\)

\(\therefore \tan\theta = \text{____}\)

1 answer

Best answer

Answer: \(\tan\theta = \dfrac{24}{7}\)

\(1 + \tan^2\theta = \sec^2\theta\)

\(\therefore 1 + \tan^2\theta = \left(\dfrac{25}{7}\right)^2 = \dfrac{625}{49}\)

\(\therefore \tan^2\theta = \dfrac{625}{49} - 1\)

\(\therefore \tan^2\theta = \dfrac{625 - 49}{49} = \dfrac{576}{49}\)

\(\therefore \tan\theta = \dfrac{24}{7}\) (taking square roots, θ acute).

Blanks: \(\left(\dfrac{25}{7}\right)^2\); 1; 576; \(\dfrac{24}{7}\).

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report
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