A. 0 B. 1 C. sin²θ D. tan²θ

Answer: (B) 1 1 + tan²θ = sec²θ, so cos²θ × sec²θ = cos²θ × 1/cos²θ = 1.

\(\cos^2\theta\,(1 + \tan^2\theta) = \) ____ .

A. 0

B. 1

C. \(\sin^2\theta\)

D. \(\tan^2\theta\)

Doubtly Asked 29 Oct 2026 Practice test ssc 10th Save WhatsApp Report

Best answer

Answer: (B) 1

\(1 + \tan^2\theta = \sec^2\theta\), so \(\cos^2\theta \times \sec^2\theta = \cos^2\theta \times \dfrac{1}{\cos^2\theta} = 1\).

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report

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