Chapter: Trigonometry· Mathematics Part 2 (Geometry)
Answer: \(\tan\theta = \dfrac{12}{5}\)
\(5\sec\theta = 13\) \(\therefore \sec\theta = \dfrac{13}{5}\).
\(\tan^2\theta = \sec^2\theta - 1 = \dfrac{169}{25} - 1 = \dfrac{144}{25}\) \(\therefore \tan\theta = \dfrac{12}{5}\).