Chapter: Mensuration· Mathematics Part 2 (Geometry)
Answer: 56 cm\(^2\)
Area of minor sector O-AB \(= \dfrac{90}{360} \times \dfrac{22}{7} \times 14 \times 14 = \dfrac{1}{4} \times 616 = 154\) cm\(^2\).
Area of ΔOAB (right-angled at O) \(= \dfrac{1}{2} \times 14 \times 14 = 98\) cm\(^2\).
Area of minor segment = area of sector – area of triangle = 154 – 98 = 56 cm\(^2\).