Chapter: Linear Equations in Two Variables· Mathematics Part 1 (Algebra)
Answer: Fixed charge ₹ 55, rate ₹ 15 per km; a 25 km ride costs ₹ 430
Let the fixed charge be ₹ \(x\) and the rate be ₹ \(y\) per km.
\(x + 10y = 205\) …(I)
\(x + 15y = 280\) …(II)
(II) − (I): \(5y = 75 \Rightarrow y = 15\)
From (I): \(x = 205 - 150 = 55\)
For 25 km: \(55 + 25 \times 15 = 55 + 375 = ₹\ 430\).