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Answer: 3. 236.5 W

Key idea: for a refrigerator, \(\text{COP}=\dfrac{T_2}{T_1-T_2}=\dfrac{Q_2}{W}\).

  1. \(T_2=277\) K, \(T_1=303\) K, so COP \(=\dfrac{277}{26}\approx10.65\).
  2. Heat removed per second \(=600\times4.2=2520\) J/s.
  3. \(W=\dfrac{2520}{10.65}\approx236.5\) W.
Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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