1. t₁+273/t₁-t₂ 2. t₂+273/t₁-t₂ 3. t₁+t₂/t₁+273 4. t₁/t₁-t₂

Answer: 1. t₁+273/t₁-t₂ The refrigerator works as a heat pump. Ideally its coefficient of performance for the heat delivered to the room is Q₁/W=T₁/T₁-T₂ . With T₁=t₁+273 and T₂=t₂+273 , the heat given to the room per joule of work is Q₁/W=t₁+273/t₁-t₂ Option (1). Option (2) is the COP of cooling ( Q₂/W ), not the heat delivered.

Topic: Second law, reversible and irreversible processes· Thermodynamics

The temperature inside a refrigerator is t_2°C and the room temperature is t_1°C. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be

1. $\frac{t_1+273}{t_1-t_2}$

2. $\frac{t_2+273}{t_1-t_2}$

3. $\frac{t_1+t_2}{t_1+273}$

4. $\frac{t_1}{t_1-t_2}$

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Answer: 1. $\frac{t_1+273}{t_1-t_2}$

The refrigerator works as a heat pump. Ideally its coefficient of performance for the heat delivered to the room is $\dfrac{Q_1}{W}=\dfrac{T_1}{T_1-T_2}$.

With $T_1=t_1+273$ and $T_2=t_2+273$, the heat given to the room per joule of work is

$$\frac{Q_1}{W}=\frac{t_1+273}{t_1-t_2}$$

Option (1). Option (2) is the COP of cooling ($Q_2/W$), not the heat delivered.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The temperature inside a refrigerator is t_2°C and the room temperature is t_1°C. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be

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