If E and G respectively denote energy and gravitational constant, then E /G has the dimensions of:

If E and G respectively denote energy and gravitational constant, then \(E\over G\) has the dimensions of:

(1) [M2 ] [L–2 ] [T–1 ] (2) [M2 ] [L–1 ] [T0 ] (3) [M] [L–1 ] [T–1 ] (4) [M] [L0 ] [T0 ]

Doubtly Asked 29 Oct 2021 Student doubt neet neet 2021 physics Save WhatsApp Report

1 answer

Best answer

Correct answer: (2) [M²] [L^-1] [T⁰]

Explanation:

E = energy = [ML²T^-2]

G = Gravitational constant = [M^-1L³T^-2]

So \(\frac{E}{G} = \frac{[E]}{[G]}\)

= \(ML^2T^{−2}\over M^{−1}L^3T^{−2}\) = [M²] [L^-1] [T⁰]

Doubtly · 29 Oct 2021 Report

Was this answer helpful?