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Topic: Internal resistance, emf, cells in series and parallel· Current Electricity

A potentiometer wire is 100 cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 50 cm and 10 cm from th…

A potentiometer wire is 100 cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 50 cm and 10 cm from the positive end of the wire in the two cases. The ratio of emf's is :

1. 5 : 1

2. 5 : 4

3. 3 : 4

4. 3 : 2

1 answer

Best answer

Answer: 4. 3 : 2

Key idea: balance length is proportional to the emf in the circuit.

  1. Supporting: \(\varepsilon_1+\varepsilon_2\propto50\); opposing: \(\varepsilon_1-\varepsilon_2\propto10\).
  2. So \(\varepsilon_1\propto30\) and \(\varepsilon_2\propto20\).
  3. Ratio \(=3:2\).
Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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