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Topic: Internal resistance, emf, cells in series and parallel· Current Electricity

A battery consists of a variable number 'n' of identical cells (having internal resistance 'r' each) which are connected in series. The terminals of the battery are short-circuited and the current I is measured. Which of the graphs shows the correct…

A battery consists of a variable number 'n' of identical cells (having internal resistance 'r' each) which are connected in series. The terminals of the battery are short-circuited and the current I is measured. Which of the graphs shows the correct relationship between I and n ?

four I vs n graphs (options)

1. (graph: I constant, horizontal line vs n)

2. (graph: I rising with decreasing slope, concave curve vs n)

3. (graph: I linear increasing vs n)

4. (graph: I rising with increasing slope, convex curve vs n)

1 answer

Best answer

Answer: 1. (graph: I constant, horizontal line vs n)

For \(n\) identical cells in series, total emf is \(nE\) and total internal resistance is \(nr\). With the terminals short-circuited there is no external resistance.

$$I=\frac{nE}{nr}=\frac Er$$

The current is independent of \(n\), so the graph of I against n is a horizontal straight line (option 1).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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