A long solenoid has 1000 turns. When a current of 4A flows through it, the magnetic flux linked with each turn of the solenoid is 4×10^-3 Wb. The self-inductance of the solenoid is :

1. 4 H

2. 3 H

3. 2 H

4. 1 H

Doubtly Asked 30 Oct 2026 NEET UG 2016 Phase 1 Practice test neet Save WhatsApp Report

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Answer: 4. 1 H

Key idea: \(L=\dfrac{N\phi}{I}\), where \(\phi\) is the flux per turn.

\(L=\dfrac{1000\times4\times10^{-3}}{4}=1\) H.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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