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Topic: Magnification, power of lens, combination of thin lenses· Optics

Match the corresponding entries of column 1 with column 2. [Where m is the magnification produced by the mirror]Column 1: (A) m = -2; (B) m = -1/2; (C) m = +2; (D) m = +1/2Column 2: (a) Convex mirror; (b) Concave mirror; (c) Real image; (d) Virtual i…

Match the corresponding entries of column 1 with column 2. [Where m is the magnification produced by the mirror]

Column 1: (A) \(m = -2\); (B) \(m = -\frac{1}{2}\); (C) \(m = +2\); (D) \(m = +\frac{1}{2}\)

Column 2: (a) Convex mirror; (b) Concave mirror; (c) Real image; (d) Virtual image

1. A\(\to\)b and c; B\(\to\)b and c; C\(\to\)b and d; D\(\to\)a and d

2. A\(\to\)a and c; B\(\to\)a and d; C\(\to\)a and b; D\(\to\)c and d

3. A\(\to\)a and d; B\(\to\)b and c; C\(\to\)b and d; D\(\to\)b and c

4. A\(\to\)c and d; B\(\to\)b and d; C\(\to\)b and c; D\(\to\)a and d

1 answer

Best answer

Answer: 1. A\(\to\)b and c; B\(\to\)b and c; C\(\to\)b and d; D\(\to\)a and d

Key idea: real images have negative \(m\) (inverted); virtual images have positive \(m\) (erect). A convex mirror always gives a virtual image with \(0

  • A, \(m=-2\): real, enlarged, so concave mirror: b and c.
  • B, \(m=-\tfrac12\): real, diminished, so concave mirror: b and c.
  • C, \(m=+2\): virtual, enlarged, so concave mirror: b and d.
  • D, \(m=+\tfrac12\): virtual, diminished, so convex mirror: a and d.

This matches option 1.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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