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Answer: 1. 24.1 s

Key idea: for a first-order reaction, rate = \(k[A]\), so the ratio of rates equals the ratio of concentrations.

\([A]_{10}/[A]_{20}=0.04/0.03=4/3\).

Also \(\ln([A]_{10}/[A]_{20}) = k(20-10)\), so

$$k=\frac{\ln(4/3)}{10}=\frac{0.2877}{10}=0.02877\ \mathrm{s^{-1}}$$

$$t_{1/2}=\frac{0.693}{k}=\frac{0.693}{0.02877}\approx 24.1\ \mathrm{s}$$

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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