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Topic: Ethers· Organic Compounds Containing Oxygen

The reaction[cyclopentanol, then NaH giving sodium cyclopentoxide, then Me-I giving methyl cyclopentyl ether; scheme shown in figure]can be classified as :

The reaction

[cyclopentanol, then NaH giving sodium cyclopentoxide, then Me-I giving methyl cyclopentyl ether; scheme shown in figure]

can be classified as :

reaction scheme: cyclopentanol + NaH -> sodium cyclopentoxide, + Me-I -> methyl cyclopentyl ether

1. Williamson ether synthesis reaction

2. Alcohol formation reaction

3. Dehydration reaction

4. Williamson alcohol synthesis reaction

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Answer: 1. Williamson ether synthesis reaction

Key idea: an alcohol is converted by a strong base (NaH) into an alkoxide, which then attacks an alkyl halide in an \(\mathrm{S_N2}\) reaction to give an ether. That is the Williamson ether synthesis.

Here cyclopentanol gives sodium cyclopentoxide, which reacts with Me-I to give methyl cyclopentyl ether. This is not an alcohol formation, not a dehydration, and there is no reaction called Williamson alcohol synthesis.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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