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Answer: 4. sp

Key idea: the carbanion carbon in \(\mathrm{CH_3C\equiv C^-}\) is triply bonded to another carbon, so it has 2 regions of electron density and is sp hybridised (one sigma bond to the other C, plus the lone pair).

The lone pair sits in an sp hybrid orbital, option 4. The higher s-character (50%) is the reason terminal alkynes are acidic.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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