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Answer: 1. 10 \(\sigma\) bonds and 3 \(\pi\) bonds

Count every bond in pent-2-en-4-yne, \(\mathrm{CH_3-CH=CH-C\equiv CH}\). A single bond is one \(\sigma\); a double bond is 1 \(\sigma\) + 1 \(\pi\); a triple bond is 1 \(\sigma\) + 2 \(\pi\).

  • C-C \(\sigma\) bonds: 4 (including the \(\sigma\) of the double and triple bonds)
  • C-H \(\sigma\) bonds: 3 + 1 + 1 + 1 = 6
  • Total \(\sigma\) = 10
  • \(\pi\) bonds: 1 (double) + 2 (triple) = 3

So the molecule has 10 \(\sigma\) and 3 \(\pi\) bonds, option (1).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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