1. 46 Ω 2. 26 Ω 3. 13 Ω 4. 230 Ω

Answer: 2. 26 Ω The bulb rated 500 W at 100 V must carry its rated current for full power. Rated current I=P/V=500/100=5 A. Supply 230 V; bulb takes 100 V, so the series resistor takes 130 V. R=130/5=26\ Ω Option (2).

Topic: Electrical energy and power· Current Electricity

A filament bulb (500 W, 100 V) is to be used in a 230 V main supply. When a resistance R is connected in series, it works perfectly and the bulb consumes 500 W. The value of R is

1. 46 $\Omega$

2. 26 $\Omega$

3. 13 $\Omega$

4. 230 $\Omega$

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Answer: 2. 26 $\Omega$

The bulb rated 500 W at 100 V must carry its rated current for full power.

Rated current $I=\dfrac{P}{V}=\dfrac{500}{100}=5$ A.
Supply 230 V; bulb takes 100 V, so the series resistor takes 130 V.

$$R=\frac{130}{5}=26\ \Omega$$

Option (2).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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A filament bulb (500 W, 100 V) is to be used in a 230 V main supply. When a resistance R is connected in series, it works perfectly and the bulb consumes 500 W. The value of R is

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