Two resistors of resistance, 100 Ω and 200 Ω are connected in parallel in an electrical circuit. The ratio of the thermal energy developed in 100 Ω to that in 200 Ω in a given time is :

1. 4 : 1

2. 1 : 2

3. 2 : 1

4. 1 : 4

Doubtly Asked 30 Oct 2026 NEET UG 2022 Practice test neet Save WhatsApp Report

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Answer: 3. 2 : 1

In a parallel connection both resistors have the same voltage, so heat produced in a given time depends inversely on resistance.

\(H=\dfrac{V^2}{R}t\Rightarrow \dfrac{H_{100}}{H_{200}}=\dfrac{R_2}{R_1}=\dfrac{200}{100}=2:1\)

Option (3) is correct. If the resistors were in series (same current), the ratio would be \(1:2\), which is the trap in option (2).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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