The given circuit has two ideal diodes connected as shown in the figure below. The current flowing through the resistance R_1 will be

The given circuit has two ideal diodes connected as shown in the figure below. The current flowing through the resistance $R_1$ will be

10 V source, R1=2 ohm, diodes D1,D2 with R2=3 ohm, R3=2 ohm

1. 10.0 A

2. 1.43 A

3. 3.13 A

4. 2.5 A

Doubtly Asked 30 Oct 2026 NEET UG 2016 Phase 2 Practice test neet Save WhatsApp Report

1 answer

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Answer: 4. 2.5 A

An ideal diode conducts only when forward biased. From the figure, the battery drives current through $R_1$ and then to the two diode branches.

$D_1$ (with $R_2$) is connected the opposite way, so it is reverse biased and carries no current.
$D_2$ (with $R_3$) is forward biased and acts as a plain wire.

The circuit is 10 V across $R_1+R_3=2+2=4\ \Omega$.

$$I=\frac{10}{4}=2.5\ \text{A}$$

Option (4).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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