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Answer: 4. 0

Colour blindness is X-linked recessive. Let the normal allele be X and the defective allele Xc.

Father: XcY. Mother (homozygous normal): XX.

Sons receive the Y chromosome from the father and an X from the mother, so all sons are XY with a normal X. Probability of a colour-blind son = 0. (All daughters would be carriers.)

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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