1. 11.52 S cm ² /mol 2. 0.086 S cm ² /mol 3. 28.8 S cm ² /mol 4. 2.88 S cm ² /mol

Answer: 1. 11.52 S cm ² /mol Key idea: molar conductivity Lambda_m=kappa×1000/M (S cm ² mol ⁻¹ , kappa in S cm ⁻¹ , M in mol/L). Lambda_m=frac5.76×10⁻³×1000M The given answer 11.52 S cm ² /mol corresponds to M=0.5 M, giving 5.76/0.5=11.52 .

Topic: Conductance, molar conductivity and its variation with concentration· Redox Reactions and Electrochemistry

The molar conductivity of a [obscured] solution of AgNO_3 with electrolytic conductivity of 5.76×10^-3 S cm^-1 at 298 K is

1. $11.52$ S cm$^2$/mol

2. $0.086$ S cm$^2$/mol

3. $28.8$ S cm$^2$/mol

4. $2.88$ S cm$^2$/mol

Doubtly Asked 30 Oct 2026 NEET UG 2016 Phase 2 Practice test neet Save WhatsApp Report

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Answer: 1. $11.52$ S cm$^2$/mol

Key idea: molar conductivity $\Lambda_m=\dfrac{\kappa\times1000}{M}$ (S cm$^2$ mol$^{-1}$, $\kappa$ in S cm$^{-1}$, M in mol/L).

$$\Lambda_m=\frac{5.76\times10^{-3}\times1000}{M}$$

The given answer 11.52 S cm$^2$/mol corresponds to $M=0.5$ M, giving $5.76/0.5=11.52$.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The molar conductivity of a [obscured] solution of AgNO_3 with electrolytic conductivity of 5.76×10^-3 S cm^-1 at 298 K is

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