1. 3.34 cm ⁻¹ 2. 1.34 cm ⁻¹ 3. 3.28 cm ⁻¹ 4. 1.26 cm ⁻¹

Answer: 4. 1.26 cm ⁻¹ Key idea: Cell constant = kappa × R . G^* = 0.0210\ Ω⁻¹mathrmcm⁻¹ × 60\ Ω = 1.26\ mathrmcm⁻¹ . Option 4.

The conductivity of centimolar solution of KCl at 25°C is 0.0210 ohm^-1 cm^-1 and the resistance of the cell containing the solution at 25°C is 60 ohm. The value of cell constant is -

1. 3.34 cm\(^{-1}\)

2. 1.34 cm\(^{-1}\)

3. 3.28 cm\(^{-1}\)

4. 1.26 cm\(^{-1}\)

Doubtly Asked 30 Oct 2026 NEET UG 2023 Practice test neet Save WhatsApp Report

Best answer

Answer: 4. 1.26 cm\(^{-1}\)

Key idea: Cell constant \(= \kappa \times R\).

\(G^* = 0.0210\ \Omega^{-1}\mathrm{cm^{-1}} \times 60\ \Omega = 1.26\ \mathrm{cm^{-1}}\). Option 4.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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