Topic: Law of chemical equilibrium, Kp and Kc· Equilibrium

A 20 litre container at 400 K contains CO_2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the co…

A 20 litre container at 400 K contains \(CO_2\)(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of \(CO_2\) attains its maximum value, will be :

(Given that : \(SrCO_3(s) \rightleftharpoons SrO(s) + CO_2(g)\), \(K_p = 1.6\) atm)

1. 10 litre

2. 4 litre

3. 2 litre

4. 5 litre

Doubtly Asked 30 Oct 2026 NEET UG 2017 Practice test neet Save WhatsApp Report

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Answer: 4. 5 litre

Key idea: for \(SrCO_3(s)\rightleftharpoons SrO(s)+CO_2(g)\), \(K_p = p_{CO_2}\) at equilibrium, so the maximum pressure of \(\mathrm{CO_2}\) is 1.6 atm.

Initially \(p=0.4\) atm in 20 L (below 1.6, so no reaction). Compressing the gas, Boyle's law applies until \(p\) reaches 1.6 atm:

\(0.4\times20 = 1.6\times V\Rightarrow V=5\) L.

Below 5 L, extra \(\mathrm{CO_2}\) would combine with SrO to keep the pressure at 1.6 atm.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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A 20 litre container at 400 K contains CO_2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the co…

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