Consider the following reaction in a sealed vessel at equilibrium with concentrations of N₂ = 3.0×10⁻³ M, O₂ = 4.2×10⁻³ M and NO = 2.8×10⁻³ M. 2NO_((g)) ⇌ N_(2(g)) + O_(2(g)) If 0.1 mol L⁻¹ of NO_((g)) is taken in a closed vessel, what will be degree of dissociation ( α ) of NO_((g)) at equilibrium? 1. 0.717 2. 0.00889 3. 0.0889 4. 0.8889

Answer: 1. 0.717 Key idea: get K_c from the first data set, then use it for the new mixture. K_c=[N₂][O₂]/[NO]²=frac(3.0×10⁻³)(4.2×10⁻³)(2.8×10⁻³)²=1.607 Start with 0.1 M NO with degree of dissociation α : [NO]=0.1(1-α) , [N₂]=[O₂]=0.05α . K_c=[α/2(1-α)]²=1.607⇒α/2(1-α)=1.268 α=2.536(1-α) , so α=2.536/3.536=0.717 . Option 1.

Topic: Law of chemical equilibrium, Kp and Kc· Equilibrium

Consider the following reaction in a sealed vessel at equilibrium with concentrations of N_2 = 3.0×10^-3 M, O_2 = 4.2×10^-3 M and NO = 2.8×10^-3 M.2NO_(g) ⇌ N_2(g) + O_2(g)If 0.1 mol L^-1 of NO_(g) is taken in a closed vessel, what will be degree of…

Consider the following reaction in a sealed vessel at equilibrium with concentrations of $N_2 = 3.0\times10^{-3}$ M, $O_2 = 4.2\times10^{-3}$ M and $NO = 2.8\times10^{-3}$ M.

$2NO_{(g)} \rightleftharpoons N_{2(g)} + O_{2(g)}$

If 0.1 mol $L^{-1}$ of $NO_{(g)}$ is taken in a closed vessel, what will be degree of dissociation ($\alpha$) of $NO_{(g)}$ at equilibrium?

1. 0.717

2. 0.00889

3. 0.0889

4. 0.8889

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Answer: 1. 0.717

Key idea: get $K_c$ from the first data set, then use it for the new mixture.

$$K_c=\frac{[N_2][O_2]}{[NO]^2}=\frac{(3.0\times10^{-3})(4.2\times10^{-3})}{(2.8\times10^{-3})^2}=1.607$$

Start with 0.1 M NO with degree of dissociation $\alpha$: $[NO]=0.1(1-\alpha)$, $[N_2]=[O_2]=0.05\alpha$.

$$K_c=\left[\frac{\alpha}{2(1-\alpha)}\right]^2=1.607\Rightarrow\frac{\alpha}{2(1-\alpha)}=1.268$$

$\alpha=2.536(1-\alpha)$, so $\alpha=2.536/3.536=0.717$. Option 1.

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Consider the following reaction in a sealed vessel at equilibrium with concentrations of N_2 = 3.0×10^-3 M, O_2 = 4.2×10^-3 M and NO = 2.8×10^-3 M.2NO_(g) ⇌ N_2(g) + O_2(g)If 0.1 mol L^-1 of NO_(g) is taken in a closed vessel, what will be degree of…

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