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Topic: Polarization, Brewster's law, Polaroids· Optics

Two Polaroids P_1 and P_2 are placed with their axis perpendicular to each other. Unpolarised light I_0 is incident on P_1. A third polaroid P_3 is kept in between P_1 and P_2 such that its axis makes an angle 45^° with that of P_1. The intensity of…

Two Polaroids \(P_1\) and \(P_2\) are placed with their axis perpendicular to each other. Unpolarised light \(I_0\) is incident on \(P_1\). A third polaroid \(P_3\) is kept in between \(P_1\) and \(P_2\) such that its axis makes an angle 45\(^\circ\) with that of \(P_1\). The intensity of transmitted light through \(P_2\) is :

1. \(\frac{I_0}{4}\)

2. \(\frac{I_0}{8}\)

3. \(\frac{I_0}{16}\)

4. \(\frac{I_0}{2}\)

1 answer

Best answer

Answer: 2. \(\frac{I_0}{8}\)

Key idea: the first polaroid halves unpolarised light; then use Malus's law \(I=I\cos^2\theta\).

After \(P_1\): \(\dfrac{I_0}{2}\). After \(P_3\) (45\(^\circ\)): \(\dfrac{I_0}{2}\cos^245^\circ=\dfrac{I_0}{4}\).

\(P_2\) is at 45\(^\circ\) to \(P_3\): \(\dfrac{I_0}{4}\cos^245^\circ=\dfrac{I_0}{8}\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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