Topic: Fluid pressure, Pascal's law and applications· Properties of Solids and Liquids

A U tube with both ends open to the atmosphere, is partially filled with water. Oil, which is immiscible with water, is poured into one side until it stands at a distance of 10 mm above the water level on the other side. Meanwhile the water rises by…

A U tube with both ends open to the atmosphere, is partially filled with water. Oil, which is immiscible with water, is poured into one side until it stands at a distance of 10 mm above the water level on the other side. Meanwhile the water rises by 65 mm from its original level (see diagram). The density of the oil is :

U-tube with oil on left, water, labels 10 mm, 65 mm, initial and final water level, points A-F

1. 425 kg m\(^{-3}\)

2. 800 kg m\(^{-3}\)

3. 928 kg m\(^{-3}\)

4. 650 kg m\(^{-3}\)

Doubtly Asked 30 Oct 2026 NEET UG 2017 Practice test neet Save WhatsApp Report

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Answer: 3. 928 kg m\(^{-3}\)

Key idea: pressure at the same level in the same liquid is equal. Take points B (oil-water interface, left) and C (same level in water, right).

The oil column from A to B is \(10+65+65=140\) mm. The water column from C up to the final level E is \(65+65=130\) mm.

\(140\,\rho_{oil}g=130\times1000\,g\Rightarrow\rho_{oil}=\dfrac{130000}{140}\approx928\) kg m\(^{-3}\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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A U tube with both ends open to the atmosphere, is partially filled with water. Oil, which is immiscible with water, is poured into one side until it stands at a distance of 10 mm above the water level on the other side. Meanwhile the water rises by…

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