In the circuits shown below, the readings of the voltmeters and the ammeters will be : 1. V₂ > V₁ and i₁ = i₂ 2. V₁ = V₂ and i₁ > i₂ 3. V₁ = V₂ and i₁ = i₂ 4. V₂ > V₁ and i₁ > i₂

Answer: 3. V₁ = V₂ and i₁ = i₂ Treat the voltmeters as ideal (infinite resistance), so they draw no current. Circuit 1: the 10 Ω resistor is across the 10 V battery. V₁=10 V and i₁=10/10=1 A. Circuit 2: the voltmeter is in series with the second 10 Ω resistor, and no current flows in that branch. So no voltage drops across that resistor and the voltmeter reads the full 10 V. The current is only through the first resistor, i₂=1 A. So V₁=V₂ and i₁=i₂ .

Topic: Series and parallel combination of resistors· Current Electricity

In the circuits shown below, the readings of the voltmeters and the ammeters will be :

Circuit 1 and Circuit 2: 10 ohm resistor, voltmeter, ammeter and 10 V battery

1. \(V_2 > V_1\) and \(i_1 = i_2\)

2. \(V_1 = V_2\) and \(i_1 > i_2\)

3. \(V_1 = V_2\) and \(i_1 = i_2\)

4. \(V_2 > V_1\) and \(i_1 > i_2\)

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Answer: 3. \(V_1 = V_2\) and \(i_1 = i_2\)

Treat the voltmeters as ideal (infinite resistance), so they draw no current.

Circuit 1: the 10 \(\Omega\) resistor is across the 10 V battery. \(V_1=10\) V and \(i_1=\dfrac{10}{10}=1\) A.
Circuit 2: the voltmeter is in series with the second 10 \(\Omega\) resistor, and no current flows in that branch. So no voltage drops across that resistor and the voltmeter reads the full 10 V. The current is only through the first resistor, \(i_2=1\) A.

So \(V_1=V_2\) and \(i_1=i_2\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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In the circuits shown below, the readings of the voltmeters and the ammeters will be :

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