1. R/64 2. R/32 3. R/16 4. R/8

A wire of resistance R is cut into 8 equal pieces. From these pieces two equivalent resistances are made by adding four of these together in parallel. Then these two sets are added in series. The net effective resistance of the combination is :

1. $\frac{R}{64}$

2. $\frac{R}{32}$

3. $\frac{R}{16}$

4. $\frac{R}{8}$

Doubtly Asked 30 Oct 2026 NEET UG 2025 Practice test neet Save WhatsApp Report

Best answer

Answer: 3. $\frac{R}{16}$

Key idea: cutting a wire into equal parts divides its resistance equally.

Each piece has resistance $R/8$. Four in parallel give $\dfrac{R/8}{4}=\dfrac R{32}$. Two such sets in series:

$$R_{net}=\frac R{32}+\frac R{32}=\frac R{16}$$

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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