Skip to content
doubtly

1 answer

Best answer

Answer: 3. C\(_2\)

Write the MO configuration for each molecule.

  • \(\mathrm{C_2}\) (12 electrons): \(\sigma_{1s}^2\sigma_{1s}^{*2}\sigma_{2s}^2\sigma_{2s}^{*2}\pi_{2p}^4\). The 2p electrons occupy only the two \(\pi\) orbitals, so the bonding is two \(\pi\) bonds with no net \(\sigma\) bond.
  • \(\mathrm{N_2}\): has \(\sigma_{2p}^2\) too, so one \(\sigma\) and two \(\pi\).
  • \(\mathrm{O_2}\): one \(\sigma\) and one \(\pi\) net.
  • \(\mathrm{Be_2}\): bond order zero, not formed.

Answer: option (3).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.