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Topic: Molecular orbital theory, bond order, bond length, bond energy· Chemical Bonding and Molecular Structure

The correct order of energies of molecular orbitals of N_2 molecule, is :

1. \(\sigma 1s<\sigma^* 1s<\sigma 2s<\sigma^* 2s<(\pi 2p_x=\pi 2p_y)<(\pi^* 2p_x=\pi^* 2p_y)<\sigma 2p_z<\sigma^* 2p_z\)

2. \(\sigma 1s<\sigma^* 1s<\sigma 2s<\sigma^* 2s<(\pi 2p_x=\pi 2p_y)<\sigma 2p_z<(\pi^* 2p_x=\pi^* 2p_y)<\sigma^* 2p_z\)

3. \(\sigma 1s<\sigma^* 1s<\sigma 2s<\sigma^* 2s<\sigma 2p_z<(\pi 2p_x=\pi 2p_y)<(\pi^* 2p_x=\pi^* 2p_y)<\sigma^* 2p_z\)

4. \(\sigma 1s<\sigma^* 1s<\sigma 2s<\sigma^* 2s<\sigma 2p_z<\sigma^* 2p_z<(\pi 2p_x=\pi 2p_y)<(\pi^* 2p_x=\pi^* 2p_y)\)

1 answer

Best answer

Answer: 2. \(\sigma 1s<\sigma^* 1s<\sigma 2s<\sigma^* 2s<(\pi 2p_x=\pi 2p_y)<\sigma 2p_z<(\pi^* 2p_x=\pi^* 2p_y)<\sigma^* 2p_z\)

Key idea: For molecules with 14 or fewer electrons (\(\mathrm{B_2, C_2, N_2}\)), s-p mixing puts the \(\pi 2p\) orbitals below \(\sigma 2p_z\).

The order for \(\mathrm{N_2}\) is \(\sigma 1s < \sigma^*1s < \sigma 2s < \sigma^*2s < (\pi 2p_x = \pi 2p_y) < \sigma 2p_z < (\pi^*2p_x = \pi^*2p_y) < \sigma^*2p_z\). This is option 2. The order with \(\sigma 2p_z\) below \(\pi 2p\) holds for \(\mathrm{O_2}\) and \(\mathrm{F_2}\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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